Right choice is (b) 2πe^aω u(-ω)
The best explanation: Let X(t) = \(\frac{1}{a+jt}\)
Replacing t with ω
X(ω) = \(\frac{1}{a+jw}\)
x(t )= e^-at u(t)
As per duality property X(t) ↔ 2πx(-ω), we have
\(F[X(t)] = F\Big[\frac{1}{a+jt}\Big]\) = 2πx(-ω) = 2πe^aω u(-ω).