The correct choice is (c) \(e^{-jk \frac{8π}{T}} X[k]\)
Easiest explanation: The period of x (4t) is a fourth of the period of x (t). The Fourier series coefficient of x (4t) is still X[k]. Hence, the coefficient of x (4t-1) is \(e^{-jk \frac{8π}{T}} X[k]\).