Question

For the circuit given below, the value of the hybrid parameter h12 is ___________

(a) 6 Ω

(b) 5 Ω

(c) 1 Ω

(d) 2 Ω

The question was posed to me in homework.

The doubt is from Hybrid (h) Parameter topic in division Two-Port Networks of Network Theory

Answer 1

Right choice is (c) 1 Ω

The best I can explain: Hybrid parameter h12 is given by, h12 = \(\frac{V_1}{V_2}\), when I1 = 0.

Therefore short circuiting the terminal X-X’ we get,

V1 = IA × 10

IA = \(\frac{I_2}{2}\)

V2 = IB × 10

IB = \(\frac{I_2}{2}\)

From the above 4 equations, we get,

∴ \(\frac{V_1}{V_2} = \frac{I_2×10}{I_2×10}\) = 1

Hence h12 = 1 Ω.