Question

For the circuit given below, the value of the hybrid parameter h22 is ___________

(a) 0.2 Ω

(b) 0.5 Ω

(c) 0.1 Ω

(d) 0.3 Ω

I had been asked this question in an interview for internship.

This is a very interesting question from Hybrid (h) Parameter in division Two-Port Networks of Network Theory

Answer 1

Correct answer is (a) 0.2 Ω

To explain I would say: Hybrid parameter h22 is given by, h22 = \(\frac{I_2}{V_2}\), when I1 = 0.

Therefore short circuiting the terminal X-X’ we get,

V1 = IA × 10

IA = \(\frac{I_2}{2}\)

V2 = IB × 10

IB = \(\frac{I_2}{2}\)

From the above 4 equations, we get,

∴ \(\frac{I_2}{V_2}  = \frac{I_2×2}{I_2×10}\) = 0.2

Hence h22 = 0.2 Ω.