Correct choice is (a) 0.2 Ω
The explanation: Hybrid parameter h22 is given by, h22 = \(\frac{I_2}{V_2}\), when I1 = 0.
Therefore short circuiting the terminal X-X’ we get,
V1 = IA × 5
V2 = IA × 5
IA = I2
From the above equations, we get,
∴ \(\frac{I_2}{V_2} = \frac{I_2}{I_2×5}\) = 0.2
Hence h22 = 0.2 Ω.