The correct choice is (c) 1 Ω
For explanation: Hybrid parameter h12 is given by, h12 = \(\frac{V_1}{V_2}\), when I1 = 0.
Therefore short circuiting the terminal X-X’ we get,
V1 = IA × 5
V2 = IA × 5
From the above equations, we get,
∴ \(\frac{V_1}{V_2} = \frac{I_A×10}{I_A×10}\) = 1
Hence h12 = 1 Ω.