The correct answer is (a) 69.65°C
Easiest explanation: Equation for diode current
I=I0×(e^(V/ηVT)-1) where I0 = reverse saturation current
η = ideality factor
VT = thermal voltage
V = applied voltage
I0 = 10^-9A, η = 1.4, V = 0.6V, I = 2mA
We know thermal voltage VT = TK/11600. Therefore, TK = VTx11600 = 0x11600 = 342.65K = 69.65°C.