Right option is (a) 9.156mA
The explanation is: Equation for diode current
I=I0×(e^(V/ηVT)-1) where I0 = reverse saturation current
η = ideality factor
VT = thermal voltage
V = applied voltage
Since in this question ideality factor is not mentioned it can be taken as one.
I0 = 1.17 x 10^-9A, VT = 0.0252V, η = 1, V = 0.4V
Therefore, I = 1.17×10^-9xe^0.4/0.025 -1 = 9.156mA.