The correct choice is (b) 1.84mA
Best explanation: Let VD be the voltage of diode, then by Kirchoff’s loop rule
3V = 2VD + IR1
This method of assumption contains small error but it is the simplest method.
Let VD be 0.6V. Now the current I = (3-1.2)/1k = 1.8mA.
The VD = VT ln((I/IO)+1) = 0.58V
Hence current is (3-(2×0.58))/1k = 1.84mA.