Right answer is (a) 45.85°C
The explanation is: Equation for diode current
where I0 = reverse saturation current
η = ideality factor
VT = thermal voltage
V = applied voltage
Since in this question ideality factor is not mentioned it can be taken as one.
VD = 3-(2mAx1.3k) = 0.4V
VT = T/11600
Thus Temperature, T = 11600×0.0275 = 319 Kelvin = 45.85°C.