Correct choice is (a) 2.4mA
The best explanation: Let VD be the voltage of diode, then by Kirchoff’s loop rule
3V = VD + IR1
This method of assumption contains small error but it is the simplest method.
Let VD be 0.7V. Now the current I = (3-0.7)/1k = 2.3mA. Now the diode voltage for 2.3mA
VD = VT ln(I/I^0) = 0.026 x ln((2.3×10^(-3))/10^(-12)) = 0.5864V.
Now the current becomes (3-0.5864)/1000 = 2.41mA.