Correct option is (d) yp = 2 cosx – 4 sinx
For explanation I would say: ∅(x) = 20 cos x,we assume P.I in the form yp = a cosx + b sinx ….(1)
and since A.E has m = 1,3 as roots,∓i are not roots of A.E.we have to find a and b
such that yp” – 4yp‘ + 3yp = 20 cosx……(2)
from (1) we get yp‘ = – a sinx + b cosx, yp” = – a cosx – b sinx, (2) becomes
– a cosx – b sinx – 4( – a sinx + b cosx) + 3(a cosx + b sinx) = 20 cos x
(2a – b)cos x + (4a + 2b)sin x = 20 cos x –> 2a – b = 20 and 4a + 2b = 0, by solving we get
a = 2, b = – 4 from (1) yp = 2 cosx – 4 sinx is the particular integral solution.