Correct answer is (b) 75.5°
For explanation I would say: The nulls of the N- element array is given by
\(θ_n=cos^{-1}(\frac{λ}{2πd} [-β±\frac{2πn}{N}])=cos^{-1}(\frac{λ}{2πd} [±\frac{2πn}{N}])\)
⇨ \(θ_n=cos^{-1}(\frac{λ}{2π(λ/2)} [±\frac{2πn}{N}])=cos^{-1} (±\frac{2n}{8})=cos^{-1} (±\frac{n}{4}) \)
⇨ \(n=1 (first \,null) cos^{-1} (±\frac{n}{4})=cos^{-1} (±\frac{1}{4})=75.5°. \)