The correct choice is (c) 2xy’+ y(y’)^2-y=0
Easiest explanation: The equation is, y^2=4ax+4a^2……………………………………. (1)
Differentiating (1) with respect to x, we get,
2yy’=4a ………………………………………………………………………………………….. (2)
Therefore, substituting the value of 4a in (1), we get,
y^2=2yy’x+(yy’)^2
So, the required differential equation is given by,
2xy’+y(y’)^2-y=0